X+3=x^2-10x+25

Solution for X+3=x^2-10x+25 equation:

X+3=X^2-10X+25

We move all terms to the left:

X+3-(X^2-10X+25)=0

We get rid of parentheses

-X^2+X+10X-25+3=0

We add all the numbers together, and all the variables

-1X^2+11X-22=0

a = -1; b = 11; c = -22;
Δ = b2-4ac
Δ = 112-4·(-1)·(-22)
Δ = 33
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-\sqrt{33}}{2*-1}=\frac{-11-\sqrt{33}}{-2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+\sqrt{33}}{2*-1}=\frac{-11+\sqrt{33}}{-2}
$